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0.14x^2-x-3.61=0
We add all the numbers together, and all the variables
0.14x^2-1x-3.61=0
a = 0.14; b = -1; c = -3.61;
Δ = b2-4ac
Δ = -12-4·0.14·(-3.61)
Δ = 3.0216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{3.0216}}{2*0.14}=\frac{1-\sqrt{3.0216}}{0.28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{3.0216}}{2*0.14}=\frac{1+\sqrt{3.0216}}{0.28} $
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